vowel or constant letter, and detriment if it's an even or odd letter.

 You will be given one single character, you're supposed to determine if it's a vowel or constant letter, and detriment if it's an even or odd letter.

*Note 1: Vowel letters are a, o, u, i, and e.
*Note 2: We will assume that the first letter of the alphabet is odd.
*Note 3: You can be given both capital or small letters.

#include <iostream> using namespace std; int main() { char alph; cout<<"Enter c char : "<<endl; cin>>alph; int n; string a; // tolower() toupper() char ch=tolower(alph); string x="abcdefghijklmnopqrstuvwxyz"; int len = x.length(); for(int i=0;i<len;i++) { n=i+1; if(x[i]==ch) { if(n%2==0) { a="Even"; } else { a="Odd" ; } } } if(ch =='a' || ch=='e' || ch=='o' || ch=='i'||ch=='u') { cout<<"Vowel "<<a; } else{ cout<<"Constant "<<a; } }